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Samuel’s jumps in a triple jump were 4 5/6 , 3 1/3 , and 2 1/2 feet . What was the total length of his jump

User Kamwysoc
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1 Answer

6 votes

Answer:

10 2/3 ft

Explanation:

The total length he jumped is the sum of the three jumps

4 5/6 + 3 1/3 + 2 1/2

Get a common denominator

4 5/6 + 3 1/3 *2/2 + 2 1/2*3/3

4 5/6 + 3 2/6 + 2 3/6

Add the whole numbers and the fractions

4+3+2 + (5+2+3)/6

9 + 10/6

Changing the improper fraction to a whole number and a fraction

9 + 6/6 + 4/6

9+1+4/6

10 4/6

Simplifying the fraction

10 2/3

User Morteza Rastgoo
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