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a line has the equation 4x-3y+9=0. Find an equation of a line parallel to this line that has a y-intercept of -1

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Answer:

y = (4/3)x - 1

Explanation:

"a y-intercept of -1" means that the line passes thru the point (0, -1).

Solving 4x-3y+9=0 for y is one way to determine the slope, m:

-3y = -4x - 9, and so:

y = (4/3)x + 3. The slope is 4/3.

Starting with the slope-intercept form of the equation of a str. line,

y = mx + b, we get:

-1 = (4/3)(0) + b. Then b = -1, and the equation is y = (4/3)x - 1.

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