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1 vote

f(x) = {2}^(x) + 3
What is the value of f(-2)​

1 Answer

4 votes

The function is given
f(x)=2^x+3.

Now let's solve for
f(-2).


f(-2)=2^(-2)+3

Rule of negative exponent:
x^(-1)=(1)/(x^1).


f(-2)=(1)/(2^2)+3


f(-2)=(1)/(4)+(3)/(1)

Rule for sum of fractions:
(a)/(b)+(c)/(d)=(ad+bc)/(bd).


f(-2)=(13)/(4)

And the result is:


f(-2)=\boxed{(13)/(4)=3.25}

User Ttzn
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