Question

What is the factorization of the trinomial below -x^2+2x+48

Answer 1

-(x+6)(x-8)

Explanation:

-x²+2x+48

take out the negative

-(x²-2x-48)

factors of 48 with a difference of -2

-8, 6

-(x+6)(x-8)

Answer 2

`-(x-8)(x+6)`

Explanation:

The given trinomial is

`-x^2+2x+48`

By comparing to
`ax^2+bx+c`, we
`a=-1,b=2,c=48`.

`ac=-1* 48=-48`

Two factors of -48 that adds up to 2 are 8,-6.

We split the middle term to obtain;

`-x^2+8x-6x+48`

We now factor by grouping;

`-x(x-8)-6(x-8)`

We factor further to obtain;

`(x-8)(-x-6)`

`-(x-8)(x+6)`