Answer:
92.6 kJ.
Step-by-step explanation:
∵ ΔG°rxn = - nFE°cell,
Where, ΔG°rxn is the standard free energy change (J).
n is the no. of electrons in the reaction (n =2).
F is Faraday constant (C/mol) (F = 96500 C/mol).
E°cell is the standard cell potential (E°cell = - 0.48 V).
∴ ΔG°rxn = - nFE°cell = - (2)(96500 C/mol)(- 0.48 V) = 92640 J = 92.64 kJ.