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I’m gonna ask this question again can someone help me solve this and leave in terms of pi

I’m gonna ask this question again can someone help me solve this and leave in terms-example-1
User David Leal
by
3.5k points

2 Answers

28 votes
28 votes

Answer:

Circumference = 10
\pi, 19
\pi, 30
\pi, 16
\pi

Area = 25
\pi, 90.25
\pi, 225
\pi, 64
\pi

Explanation:

For the first row we have the radius which is 5, the diameter is 10. The formula for circumference is 2
\pir. So for this one its gonna be 2
\pi5 or 10
\pi

radius = 5

diameter = 10

circumference = 2
\pi5 or 10
\pi

area =
\pi
5^(2) or 25
\pi

for the second row

radius = 9.5

diameter = 19

circumference = 2
\pi9.5 or 19
\pi

area =
\pi
9.5^(2) or 90.25
\pi

for the third row

radius = 15

diameter = 30

circumference = 2
\pi15 or 30
\pi

area =
\pi
15^(2) or 225
\pi

for the fourth row

radius = 8

diameter = 16

circumference = 2
\pi8 or 16
\pi

area =
\pi
8^(2) or 64
\pi

User Tom Van Enckevort
by
3.3k points
28 votes
28 votes

The equation of the circumference of a circle in terms of
\pi is
2\pi r or
\pi d.

The circumference for a circle with diameter 10 is
10\pi.

The circumference for a circle with diameter 19 is
19\pi.

The circumference for a circle with diameter 30 is
30\pi.

The circumference for a circle with diameter 16 is
16\pi.

Relatively easy, right?

The equation of the area of a circle in terms of
\pi is
\pi r^2.

The area of a circle with radius 5 is
25\pi.

The area of a circle with radius 9.5 is
90.25\pi.

The area of a circle with radius 15 is
225\pi.

The area of a circle with radius 8 is
64\pi.

Hope this helped!

(By the way, I don't know why you're using hard formulas for trying to find the radius or diameter. The diameter is simply twice the radius, and the radius is simply half the diameter.)

User Rajes
by
3.4k points