Question

Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas​

Answer 1

The relative molecular mass of the gas​ : 64 g/mol

Further explanation

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas​

Solution

Graham's Law

`\tt (r_1)/(r_2)=\sqrt{(M_2)/(M_1) }`

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas​

Input the value :

`\tt (4r_2)/(r_2)=\sqrt{(M_2)/(4) }\\\\16=(M_2)/(4)\\\\M_2=64~g/mol`