Question

The function f is defined by

f(c)=x^2 +3x-10.
if f(x+5)=x^2 +kx+30, k= ?
find the smallest zero of f(x+5). x=?

Answer 1

k=13

x= -10

Explanation:

f(x)=x²+3x-10

f(x+5)=

=(x+5)(x+5)+3(x+5)-10

=x²+10x+25+3x+15-10

=x²+13x+30

0=x²+13x+30

0=(x+3)(x+10)

x= -3 or -10

-10< -3

smallest zero is -10

Answer 2

Hope this helps :)

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