Question

Find the distance between the points given.

(-3, 0) and (0, √7)

√2
4
√(13)

Answer 1

The correct answer is second option 4

Explanation:

Distance formula

Let (x₁, y₁) and (x₂, y₂) be the two points, the distance between two points is given by,

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

It is given two points (-3, 0) and (0, √7)

To find the distance

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²] = √[(0 - - 3)² + (√7 - 0)²]

= √[(0 + 3)² + (√7)²] =√[(3)² + (√7)²]

= √(9 + 7) = √16 = 4

Therefore the correct answer is 4

Answer 2

4

Explanation:

Remember that to find the distance between any two points on the plane, we should use the distance formula:

`d=√((x_2-x_1)+(y_2-y_1))`

where

`(x_1,y_1)` are the coordinates of the first point

`(x_2,y_2)` are the coordinates of the second point

We know from our problem that the first point is (-3, 0); therefore,
`x_1=-3` and
`y_1=0`. We also know that the second point is (0, √7), so
`x_2=0` and
`y_2=√(7)`.

Replacing the values:

`d=√((x_2-x_1)+(y_2-y_1))`

`d=\sqrt{(0-(-3))^2+(√(7)-2)^2 }`

`d=\sqrt{(0+3)^2+(√(7))^2 }`

`d=√((3)^2+7)`

`d=√(9+7)`

`d=√(16)`

`d=4`

We can conclude that the distance between the given points is 4.