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Given y- x ≥ 2 and y ≤ -3x+2

Given y- x ≥ 2 and y ≤ -3x+2-example-1
Given y- x ≥ 2 and y ≤ -3x+2-example-1
Given y- x ≥ 2 and y ≤ -3x+2-example-2
Given y- x ≥ 2 and y ≤ -3x+2-example-3
Given y- x ≥ 2 and y ≤ -3x+2-example-4
User NikSp
by
7.7k points

1 Answer

5 votes

Answer:

Picture 3

Explanation:

The easiest method is to see if (0,0) is the solution.

1. The line y ≤ -3x + 2 is the line pointing down, and y - x ≥ 2 is the line pointing up, since negative slopes go bottom-right.

2. y - x ≥ 2 --> plug in numbers: 0 - 0 ≥ 2 --> Not true --> the line pointing up's shading will go up, to avoid (0,0) --> Picture 3 is right.

3 (not needed in this situation). y ≤ -3x + 2 --> 0 ≤ 0 + 2 --> True --> The line pointing bottom right has (0,0) --> Picture 2 or 3 is right.

The overlap of possible answers is picture 3.

User Andrew Holmgren
by
7.6k points

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