2.8k views
6 votes
A biased dice is thrown.

Here are the probabilities of each score.
Score
1
2
3
4
5
6
Probability
0.15
0.05
0.25
0.05
0.3
0.2
The dice is thrown 300 times.
Work out the expected number of times the score will be odd.

User Thbonk
by
8.7k points

1 Answer

13 votes

Given:

A biased dice is thrown 300 times.

Table of probabilities of each score.

To find:

The expected number of times the score will be odd.

Solution:

Odd numbers on the dice are 1, 3, 5. The sum of their probability is


0.15+0.25+0.3=0.7

Even numbers on the dice are 2, 4, 6. The sum of their probability is


0.05+0.05+0.2=0.3

Now, the expected number of times the score will be odd is


\text{Expected odd number}=300* \text{Probability of getting an odd number}


\text{Expected odd number}=300* 0.7


\text{Expected odd number}=210

Therefore, the expected number of times the score will be odd is 210.

User ChristopherW
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories