Question

Please help me with these two questions, 10 points for each so in total 20!!

2- Which is an equation of the line containing the points (4,6) and (6,10) in standard form?


A: -2x+y = -8

B: -2-y = -22

C: -2+y= -2

D: 2x-y= -2


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4- Which shows the equation of the line containing the point (-2,6) And having a slope of 3 in-intercept form?


A: 3y=x+20

B: y=3x-20

C: y=3x+12

D: y= -3/2x+3

Answer 1

2x - y = 2

Explanation:

To write the equation of a line, calculate the slope between points (4,6) and (6,10). After, substitute the slope and a point into the point slope form.

`m = (y_2-y_1)/(x_2-x_1) = (10-6)/(6-4)= (4)/(2) = 2`

Substitute m = 2 and the point (4,6) into the point slope form.

`y - y_1 = m(x-x_1)\\y -6 = 2(x-4)\\y-6 = 2x - 8 \\\y = 2x - 2 \\ 2x -y = 2`