Question

A right rectangular prism has a langht of 5cm, a with of 4 cm, and a hight of 3 cm. The dimensions of the prism are doubled. What is the surface area of the enlarged prism?​

Answer 1

Given

Dimentions of the rectangular prism are

Explanation:l=5cm, b=4cm, h=3cm

If each dimension is doubled then new prism dimensions are

L=10cm, B=8cm, H=6cm

Therefore Required surface area

Total surface area(TSA) =2(LB+BH+LH)

=2[10×8+8×6+10×6]

=2(80+48+60)

=2×188

=376square cm