Question

graph the function f (x) = x^2 + 4x -5. on the coordinate plane. (a) What are the x-intercepts? (b) What are the y-intercepts? (c) What is the maximum or minimum value?

Answer 1

a) (-5,0) and (1,0)

b) (0,-5)

c) minimum

See attached graph.

Explanation:

To graph the function, find the vertex of the function find (-b/2a, f(-b/2a)). Substitute b = 4 and a = 1.

-4/2(1) = -4/2 = -2

f(-2) = (-2)^2 + 4(-2) - 5 = 4 - 8 - 5 = -4 - 5 = -9

Plot the point (-2,-9). Then two points two points on either side like x = -1 and x = -3. Substitute x = -1 and x = -3

f(-1) = (-1)^2 + 4 (-1) - 5 = 1 - 4 - 5 = -8

Plot the point (-1,-8).

f(-3) = (-3)^2 + 4(-3) - 5 = 9 - 12 - 5 = -8

Plot the point (-3,-8).

See the attached graph.

The features of the graph are:

a) (-5,0) and (1,0)

b) (0,-5)

c) minimum