Answer:
Explanation:
Given : Carlos needs to paint the outside of the shed in his backyard, including its roof but not including its floor.
To Find: What is the total area of the surfaces that he needs to paint?
Solution:
Length of backyard= 8 feet
Breadth of backyard = 5 feet
Height of backyard = 6 feet
So, Area of walls of backyard = Lateral surface area =
![2(l+b) * h](https://img.qammunity.org/2020/formulas/mathematics/high-school/kbkaprqug18o5dpyf7hyh2ffd011o6fpci.png)
=
=
Area of two triangular faces of roof =
![(1)/(2) * Base * Height * 2](https://img.qammunity.org/2020/formulas/mathematics/high-school/8zscomm07ufzrzdnp5zb3u4lk96sj61rp0.png)
Base of triangular face = 8 feet
Height of triangular face = 3 feet
So, Area of two triangular faces of roof =
![(1)/(2) * 8 * 3 * 2](https://img.qammunity.org/2020/formulas/mathematics/high-school/ye9eko6qii1tmssbthv0kuzp1m0h26whwt.png)
=
![24 ft^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/19wzq5rndibzo4i9cxfvrq7gi18njnlt6p.png)
Area of two square roof =
![2 * Side^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/mpdrlvat52xod9qlehz241qdl5is44j9mi.png)
Side of square = 5 feet
So, Area of two square roof =
![2 * 5^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/au2nor3bcfpj0t1pfuuvtikz1zil71k7a5.png)
=
![50ft^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/n0ynguwnxm6wkmjx1j6kxcca3ryxzozulw.png)
So, total area to be painted =
=
Hence the total area of the surfaces that he needs to paint is