Question

What is the equation of the line that passes through (-2,4) (-6,10)

Answer 1

`\large\boxed{y-4=-(3)/(2)(x+2)}\to\boxed{y=-(3)/(2)x+1}\to\boxed{3x+2y=2}`

Explanation:

The point-slope form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slope

`m=(y_2-y_1)/(x_2-x_1)`

We have the points (-2, 4) and (-6, 10). Substitute:

`m=(10-4)/(-6-(-2))=(6)/(-4)=-(6)/(4)=-(3)/(2)\\\\y-4=-(3)/(2)(x-(-2))\\\\y-4=-(3)/(2)(x+2)`