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En un triangulo rectangulo ABC (B=90) REDUCE: J=(sec2C-cot2A) (sen2C+sen2A) es para hoy porfaaaa
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En un triangulo rectangulo ABC (B=90) REDUCE: J=(sec2C-cot2A) (sen2C+sen2A) es para hoy porfaaaa
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Aug 11, 2020
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En un triangulo rectangulo ABC (B=90) REDUCE:
J=(sec2C-cot2A) (sen2C+sen2A) es para hoy porfaaaa
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Rosenthal
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Answer:
puc provar, però no sé lemme see
Ususer
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Aug 18, 2020
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