Okay, let's think through this step-by-step:
* The HI bond length is given as 1.61 Å
* The measured dipole moment is 0.44 D
* We need to find the magnitude of the negative charge on I in units of e
To find the charge, we can use the formula:
μ = q*d
Where:
μ is the dipole moment (0.44 D)
q is the magnitude of charge
d is the HI bond length (1.61 Å = 1.61 x 10-10 m)
Plugging in the values:
0.44 = q * 1.61 x 10-10
q = 0.44 / (1.61 x 10-10)
q = 0.273 x 1010 C
Charges are generally expressed in units of elementary charge (e):
1 e = 1.602 x 10-19 C
Therefore, converting 0.273 x 1010 C to units of e:
q = (0.273 x 1010 C) / (1.602 x 10-19 C/e)
q = 0.170 e
Therefore, the magnitude of the negative charge on I in HI is 0.170 e.