Answer:
0.75 g of K2CO3
Step-by-step explanation:
- To prepare 150. mL of a 0.50% by volume K2CO3 solution;
- It means 0.5% w/v in 150 mL.
- Therefore, there would be 0.5 of K2CO3 in 100 mL of the solution.
- Taking the density of the solution to be equivalent to the density of water, that is, 1 g/ml.
- The mass of the solution will be; 150 mL × 1 g/mL = 150 g
Therefore; the mass of K2CO3 will be;
= 0.5/100 × 150 g
= 0.75 g