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(square root of 6+the square root of 11)/(square root of 5+square root of 3) =

2 Answers

3 votes
It should be 22.880627.
User Salsaman
by
7.6k points
7 votes

ANSWER


(√(30) + √(55)- √(33) -3√(2) )/( 2 )

Step-by-step explanation

The given radical expression is


( √(6) + √(11) )/( √(5) + √(3) )

We rationalize the denominator to get:


( √(6) + √(11) )/( √(5) + √(3) ) * (√(5) - √(3))/(√(5) - √(3))

This implies that:


(( √(6) + √(11) )(√(5) - √(3)))/( (√(5) + √(3))(√(5) - √(3)) )

We expand using the distributive property and also applying difference of two squares on the denominator.


\frac{( √(6) * √(5) - √(6) * √(3) + √(5) * √(11) - √(3) * √(11) )}{ {( √(5) )}^(2) - {( √(3) )}^(2) }

This will give us,


(√(30) - 3√(2) + √(55)-√(33) )/( 5 - 3 )


(√(30) + √(55)- √(33) -3√(2) )/( 2 )

User Heather Gaye
by
8.3k points

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