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A presidential candidate plans to begin her campaign by visiting the capitals in 4 of 45 states. What is the probability that she selects the route of four specific​ capitals?

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Answer:

1/3,575,880

Explanation:

To solve for this problem we need to find for each possibility.

We will have:

1/45 for the first route.

1/44 for the second route.

1/43 for the third route.

1/42 for the fourth route.

This is considering that the candidate will not be in the same capital twice.

So we simply multiply all of the possibilities.

1/45 x 1/44 x 1/43 x 1/42 = 1/3,575,880

So there will be a 1/3,575,880 possibility that the candidate will select the route of the four specific capitals.

User Randy Olson
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