Question

Find the value of y if VP is an angel bisector, m<2=1+28y and m

Answer 1

`\boxed{y=1}`

Explanation:

Since
`m\angle1=m\angle2` due to
`\over{VP}` is an angle bisector, we have the following:

`m\angle1+m\angle2=m\angle XVW\\(1+28y)+(1+28y)=59y-1\\2+56y=59y-1\\2+1=59y-56y\\3=3y\\y=1`