Find the value of y if VP is an angel bisector, m<2=1+28y and m

asked Sep 12, 2020 29.1k views

1 vote

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2 votes

Answer:

$\boxed{y=1}$

Explanation:

Since
$m\angle1=m\angle2$ due to
$\over{VP}$ is an angle bisector, we have the following:

$m\angle1+m\angle2=m\angle XVW\\(1+28y)+(1+28y)=59y-1\\2+56y=59y-1\\2+1=59y-56y\\3=3y\\y=1$

Src answered Sep 18, 2020

by Src

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