Answer:
A(g) + B(g) → 3C(g).
Step-by-step explanation:
As the no. of gaseous molecules increases in the product side than the reactants, disordering occurs and ΔSrxn be more positive.
as in: A(g) + B(g) → 3C(g).
the no. of gaseous molecules in the reactants side (2) and be (3) in the products side, disorder increases.
While, as the no. of gaseous molecules decreases in the product side than the reactants, ordering occurs and ΔSrxn be more negative.
as in:
2A(g) + B(g) → C(g) ,
the no. of gaseous molecules in the reactants side (3) and be (1) in the products side, ordering increases.
2A(g) + 3B(g) → 4C(g) ,
the no. of gaseous molecules in the reactants side (5) and be (4) in the products side, ordering increases.
2A(g) + B(s) → 3C(g).
the no. of gaseous molecules in the reactants side (3) and be (3) in the products side, ordering is the same.