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The half-life of radon-222 is 3.824 days. After what time will one-fourth of a given amount of radon-222 remain?

1 Answer

1 vote

Answer:

  • 7.648 days.

Step-by-step explanation:

Half-life is the time for a sample reduce its amount to the half.

The radioactie isotopes, such as radon-222, have constant half-life times.

The amount that remains after a number, n, of half-lives may be calcualted by the following exponential decay equation:


A=A_0[(1)/(2)]^n

From which you get:


(A)/(A_0)=[(1)/(2)]^n

Here, you want A/A₀ = 1/4

So, you just must to solve for n:


(1)/(4)=[(1)/(2)]^n\\ \\ (1)/(2^2)=(1)/(2^n)\\ \\ n=2

Then, two half-lives will have passed, which equals to 2×3.824 days = 7.648 days.

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