Answer:
![(1)/(60)Hz](https://img.qammunity.org/2020/formulas/physics/high-school/skdjm5t77nmuh9j6ewjd9njib8ohtc8hgr.png)
Step-by-step explanation:
The frequency of the second hand of a clock is given by
![f=(1)/(T)](https://img.qammunity.org/2020/formulas/physics/middle-school/70n1ge4t9yjxlmxiba3rirr9m8q57zz3ve.png)
where T is the period of the second hand (the time it takes to complete one cycle).
The period of the second hand is 60 seconds:
T = 60 s
Therefore, its frequency is
![f=(1)/(60 s)=(1)/(60)Hz](https://img.qammunity.org/2020/formulas/physics/high-school/pcfytv9dxi0q9ov627tys3hsptefsovcx4.png)