Answer:
a. [(2X^3) + Y] * [(-1/4) -XY]
b. Ab = [(n^2 - 1) * (4m - n)] / 2 + (4m - n)^2
Explanation:
Hello
For a:
The figure is a rectangle, then its area is Lenght*Weight, then:
Aa = [(2X^3) + Y] * [(-1/4) -XY]
For the b:
The total figure is composed by two figures, a square and a rectangle triangle:
Then, Ab = Atriangle + Asquare
Atriangle = (Base*height)/2
Atriangle = [(n^2 - 1) * (4m - n)] / 2
Asquare = Side*Side
Asquare = (4m - n)*(4m - n)
Asquare = (4m - n)^2
Then
Ab = [(n^2 - 1) * (4m - n)] / 2 + (4m - n)^2
You can to do now the reduction of terms and factorizations =D
Best regards