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What is the equation of the line that is parallel to line R, y = 2x + 5, and passes through the

point (-2, 2)?

User Lebecca
by
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1 Answer

9 votes
9 votes

Answer:

y = 2x + 6

Explanation:

We are given the line R, which is y=2x+5, and we want to find the equation of the line that is parallel to this line, and that also passes through the point (-2, 2).

Parallel lines have the same slope, yet different y-intercepts.

So, we should first find the slope of y=2x+5.

The line is written in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept.

As 2 is in the place of where m (the slope) should be, 2 is the slope of the line.

It is also the slope of the line parallel to it.

We can write the equation of the new line in slope-intercept form as well; here is the equation so far, with what we know:

y = 2x + b

We need to find b.

As the equation passes through the point (-2, 2), we can use its values to help solve for b.

Substitute -2 as x and 2 as y.

2 = 2(-2) + b

Multiply.

2 = -4 + b

Add 4 to both sides.

6 = b

Substitute 6 as b.

y = 2x + 6

User Tamarabyte
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3.0k points