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the arm of a crane is 15.0 m long and makes an angle of 70.0 degrees with the horizontal. Assume that the maximum load for the crane is limited by the amount of torque the load produce around the base
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the arm of a crane is 15.0 m long and makes an angle of 70.0 degrees with the horizontal. Assume that the maximum load for the crane is limited by the amount of torque the load produce around the base of the arm. What is the maximum torque the crank can withstand if the maximum load is 450 N. What is the Maximum load for this crane at an angle of 40.0°​

User Yinon
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To find max torque you need component of force that is perpendicular to the direction of vector r. For second part just set the equation above equal to 2308 and solve for Fmax. Only difference is the angle

the arm of a crane is 15.0 m long and makes an angle of 70.0 degrees with the horizontal-example-1
User Muhammad Faraz Ali
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