Question

What are the intercepts of the equation x-1/2y+3/2z=3?

(3,0,0)(0,-6,0)(0,0,2)
(3,0,0),(0,2,0)(0,0,6)
(-3,0,0),(0,3,0)(0,0,2)
(2,0,0)(0,3,0)(0,0,-6)

Answer 1

(3,0,0), (0,-6,0), (0,0,2)

Explanation:

Divide the equation by 3 to put it into intercept form.

x/3 + y/(-6) + z/2 = 1

The denominators are the respective intercepts:

x-intercept: 3, point (3, 0, 0)

y-intercept: -6, point (0, -6, 0)

z-intercept: 2, point (0, 0, 2)