Answer:
Option D. The student did not use the correct formula to calculate the area of the segment
Explanation:
step 1
Find the area of the isosceles triangle
Applying the law of sines
![A=(1)/(2)(12^(2))sin(60\°)=62.35\ ft^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x1mw2kh9kmu1s1k2njr1hxrxtkhbyih9a6.png)
step 2
Find the area of the sector
The area of the sector is 1/6 of the area of the circle
so
![A=\pi r^(2)/6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k5u2euw9j3am6hmd571q22s9tbxjoet7fr.png)
substitute the value
![A=(3.14)(12)^(2)/6=75.36\ ft^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e4wdbmk66cm724etdsp2a7bcw020sdrfi6.png)
step 3
Find the area of the segment
The area of the segment is equal to the area of sector minus the area of triangle
![A=75.36\ ft^(2)-62.35\ ft^(2)=13.01\ ft^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kf8iy55rd4aayd0byohaisatep466v9lof.png)
therefore
The student did not use the correct formula to calculate the area of the segment