Question

Find the first six terms of the sequence. a1 = -2, an = 3 • an-1

Answer 1

If you mean find the a1, a2, a3, a4, a5, a6.

And so we can do that:

an=3an-1

and we know a1=-2

a2=3x(a2-1)

a2=-6

a3=2x(a3-1)

a3=-12

a4=3x(a4-1)

a4=-36

a5=3xa4

a5=-108

a6=3xa5

a6=-324

Answer 2

the sequence will be ( -2, -6, -18, -54, -162, -486)

Explanation:

We have find the first six term of the sequence whic is represented by

`a_((n))=3.a_((n-1))`

amd
`a_(1)=(-2)`

First term
`a_(1)=(-2)`

`a_(2)=3(a_(1) )=3(-2) =-6`

`a_(3)=3(a_(2) )=3(-6) =-18`

`a_(4)=3(a_(3) )=3(-18) =-54`

`a_(5)=3(a_(4) )=3(-54) =-162`

`a_(6)=3(a_(5) )=3(-162) =-486`

Therefore, the sequence will be ( -2, -6, -18, -54, -162, -486)