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For a trapezoid with a height of 7 centimeters and base lengths of 6 centimeters and 10 centimeters, the area is

User Ole Wolf
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2 Answers

2 votes

Answer:

56

Explanation:


A=(1)/(2) (b1+b2)h\\


A=(1)/(2) (6+10)7


A=(1)/(2) (16)7


A=8*7


A=56

User Jlahd
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\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=6\\ b=10\\ h=7 \end{cases}\implies A=\cfrac{7(6+10)}{2} \\\\\\ A=\cfrac{7(16)}{2}\implies A=7(8)\implies A=56

User Ali Hallaji
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