Question

A force of 500 Newton’s will compress a spring 0.5 meters. What is the spring constant of the spring. Use hookes law F=kx

Answer 1

A: 1,000 m/Newton

Explanation:

Answer 2

For this case we have that Hooke's law is dadapor:

`F = kx`

Where:

F: It's the strength

x: It is the deformation when applying force

k: It is the constant of proportionality

They tell us that:

`F = 500 \ N\\x = 0.5 \ m`

We must find k.

`k = \frac {F} {x}\\k = \frac {500} {0.5}\\k = 1000 \frac {N} {m}`

Answer:

`k = 1000 \frac {N} {m}`