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What is the y-value of the vertex 4x^2 +8x-8

User IXs
by
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1 Answer

5 votes

Answer:

-12

Explanation:

Here the coefficients a, b and c are 4, 8 and -8 respectively.

-b

A formula for the axis of symmetry is x = -------

2a

-8

... which yields x = --------- = -1

2(4)

Evaluating f(x) = 4x^2 + 8x - 8 at x = -1 yields f(-1) = 4(-1)^2 + 8(-1) - 8 = -12.

The y-value of the vertex is -12. Note that the vertex lies right smack on the axis of symmetry.

User ZaxR
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5.3k points