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Solve each system using substitution or elimination. Show all required work. -10x^2+80x+y=155 5x^2-40x+y=-85

User Aizaz
by
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1 Answer

4 votes

Answer:


x = 4


y = -5

Explanation:

Given


-10x^2+80x+y=155


5x^2-40x+y=-85

Required

Solve by substitution

Make y the subject in
5x^2-40x+y=-85


5x^2-40x+y=-85


y = -5x^2 + 40x - 85

Substitute
y = -5x^2 + 40x - 85 in the first equation


-10x^2+80x+y=155


-10x^2 + 80x -5x^2 + 40x - 85 = 155

Collect Like Terms


-5x^2-10x^2 + 80x + 40x - 85 - 155=0


-15x^2 + 120x-240=0

Divide through by -15


x^2 -8x + 16 = 0


x^2 - 4x - 4x + 16 = 0


x(x - 4) - 4(x - 4) = 0


(x - 4)(x - 4) = 0


x - 4\ = 0 or
x - 4\ = 0


x = 4 or
x = 4


x = 4

Substitute 4 for x in
y = -5x^2 + 40x - 85


y = -5(4)^2 + 40 * 4 - 85


y = -5*16 + 40 * 4 - 85


y = -80 + 160 - 85


y = -5

User Davinder Singh
by
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