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9 votes
9 votes
Suppose sin(A)=-0.78. use the trig identity sin^2(A)+cos^2(A)=1 and the trig identity tan(A) = sin(A)/cos(A) to find tan(A) in quadrant IV. round to the ten-thousandth.

a. -0.2039
b. 1.3941
c. 0.8671
d. -1.2464

User Algrid
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1 Answer

5 votes
5 votes

In quadrant IV,
\cos(A) is positive. So


\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = √(1-\sin^2(A)) \approx 0.6258

Then by the definition of tangent,


\tan(A) = (\sin(A))/(\cos(A)) \approx (-0.78)/(0.6258) \approx \boxed{-1.2465}

User Leonid Veremchuk
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2.6k points