Question

Graph the first six terms of a sequence where a1 = 4 and r = 2.

Answer 1

option B is the correct answer

Explanation:

Answer 2

So the sequence will be 4, 8, 16, 32, 64, 128 .......

Explanation:

We have to graph the first six terms of a sequence with first term a = 4 and r = 2 Since r denotes common ratio so the given sequence is a geometric sequence.

Now we know the explicit formula for a geometric sequence is

`T_((n))=a(r)^(n-1)`

Since
`T_(1)` = 4

So
`T_(2)=4(2)^(2-1)` = 4 × 2 = 8

`T_(3)=4(2)^(3-1)` = 4 × 2² = 4 × 4 = 16

`T_(4)=4(2)^(4-1)` =
`(4)(2)^(3)` = 4 × 8 = 32

`T_(5)=4(2)^(5-1)` =
`4(2)^(4)` = 4 × 16 = 64

`T_(6)=4(2)^(6-1)` =
`4(2)^(5)` = 4 × 32 = 128

So the sequence will be 4, 8, 16, 32, 64, 128 .......