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What is the sum of an infinite geometric series 2=5and r=1/3

1 Answer

1 vote

Answer:

The sum to infinite = 7.5

Explanation:

Lets revise the geometric sequence

- There is a constant ratio between each two consecutive numbers

Ex:

5 , 10 , 20 , 40 , 80 , ………………………. (×2)

5000 , 1000 , 200 , 40 , …………………………(÷5)

* General term (nth term) of a Geometric Progression:

∵ U1 = a , U2 = ar , U3 = ar2 , U4 = ar3 , U5 = ar4

∴ Un = a(r^n-1), where a is the first term , r is the constant ratio

between each two consecutive terms and n is the position

of the term in the sequence

* The sum of first n terms of a Geometric Progression is calculate

from Sn = [a(1 - r^n)]/(1 - r)

* The sum to infinity of a Geometric Progression is:

S∞ = a/(1 - r), where -1 < r < 1

* In the problem a = 5 and r = 1/3

∵ a = 5 and r = 1/3

∵ S∞ = a/(1 - r)

∴ S∞ = 5/(1 - 1/3) = 5/(2/3) = 15/2 = 7.5

User Branislav
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