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4 votes
I don’t know how to solve this for questions #3 and #5?

I don’t know how to solve this for questions #3 and #5?-example-1
User Lamefun
by
5.1k points

2 Answers

1 vote

Explanation:

#3

Let's rewrite the equation in vertex form.

h(x) = -4x^2 + 24x - 41

h(x) = -4(x^2 - 6x) - 41

h(x) = -4(x^2 - 6x + 9) - 41 + 36

h(x) = -4(x - 3)^2 - 5

The vertex form is

f(x) = a(x - h)^2 + h

where point (h, k) is the vertex.

We see that h = 2, and k = -5.

The vertex is (3, -5).

The axis of symmetry is x = h.

The axis of symmetry is x = 3.

#5

The remainder theorem states that the remainder of synthetic division of the polynomial by x - c is the same as the value of the function evaluated at c. Here, c = 5, so we do the synthetic division using 5.

5| 1 9 15 -15 20

----- 5 70 425 2050

---------------------------------

1 14 85 410 2070

The remainder is 2070. That means that

f(5) = 2070

If k is a zero of function f, then f(k) = 0. Here, f(5) is not zero, so 5 is not a zero of the function.

User Bryan Ray
by
4.9k points
3 votes

Answer:

Explanation:

3) h(x) = -4x^2 + 24x -41

a)

a = -4, b = 24, and c = -41

Vertex formula: x= –b/2a

x = -24 /2(-4)

x = -24/-8

x = 3

Plug in x = 3 to find y:

= -4(3^2) + 24(3) - 41

= -4(9) + 72 - 41

= -36 + 72 - 41

= -5

Vertex (3, -5)

b) The axis of symmetry

The x-coordinate of the vertex is the axis of symmetry of the parabola

x = 3

User Danijels
by
5.5k points
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