Question

Which is the equation of a line that has a slope of -2/3 and passes through point (–3, –1)?

Answer 1

y = (-2/3)x-3

Explanation:

Hello:

equation is the line is : y = ax+b a is a slope

y = (-2/3)x+b

passing through the point (−3;−1) : -1 =(-2/3)(-3)+b so : b = -3

y = (-2/3)x-3

second solution : you can verify (-3 ; -1) in the equation : y = (-2/3)x-3