Question

One number is four times another number. Their sum is 20. What are the two numbers?

Answer 1

let two numbers be a and b

then

by question

case I

a=4b...........(1)

case II

a+b=20

4b+b=20 [from eq.1]

5b=20

b=4

then in eq.1

a=4×4

a=16

the rquired two numbers are 4 and 16.

Answer 2

4 and 16

Step-by-step explanation

Let the numbers be m and n.

Since one number is four times another number, we write;

`m = 4n...(1)`

The sum of the numbers is 20.

This gives us another equation:

`m + n = 20...(2)`

We put equation (1) into equation (2) to obtain:

`4n + n = 20`

Simplify:

`5n = 20`

Divide both sides by 5.

`n = 4`

We substitute n=4 into equation (1) to get;

`m = 4(4) = 16`

Hence the numbers are 4 and 16.