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1 vote
Which equation is represented by the graph below?

y+1= 3/2(x-4)

y-4= 3/2(x+1)

y+4= 3/2(x-1)

y-1= 3/2 (x+4)

Which equation is represented by the graph below? y+1= 3/2(x-4) y-4= 3/2(x+1) y+4= 3/2(x-example-1
User Angela D
by
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2 Answers

6 votes

Answer:

Explanation:

Hello

A (5;2)

B (-1;-7)

y = ax + b

2 = 5a + b

-7 = -a + b

2 - (-7) = 5a - (-a) + b - b

2 + 7 = 5a + a

9 = 6a

a = 9/6

a = 3/2

2 = 3/2 * 5 + b

b = 2 - 15/2

b = 4/2 - 15/2

b = 11/2

y = 3/2 x + 11/2

y+1= 3/2(x-4)

y + 1 = 3/2 x - 6

y = 3/2 x - 6 - 1

y = 3/2 x - 7 => no

y-4= 3/2(x+1)

y - 4 = 3/2 x + 3/2

y = 3/2 x + 3/2 + 4

y = 3/2 x + 3/2 + 8/2

y = 3/2 x + 11/2 => yes

y+4= 3/2(x-1)

y + 4 = 3/2 x - 3/2

y = 3/2 x - 3/2 - 4

y = 3/2 x - 3/2 - 8/2

y = 3/2 x - 11/2 => no

y-1= 3/2 (x+4)

y - 1 = 3/2 x + 6

y = 3/2 x + 6 + 1

y = 3/2 x + 7 => no

User Petia
by
8.3k points
2 votes

Answer:


y - 1 = (3)/(2)\cdot (x + 4)

Explanation:

The function is
y - 1 = (3)/(2)\cdot (x + 4), since the point (1, -4) is contained in the straight line.

User Rgm
by
8.3k points

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