Answer:
- choice d. The first reaction is a first order reaction, the second one should have an order greater than first.
Step-by-step explanation:
1) Reaction 1:
It is stated that reaction 2 has a constant half-life time.
Constant half-life time is a characteristic of first order reactions.
This fact is derived from:
- Half-life ⇒ [A / Ao] = (1/2)
- - ln (1/2) = k t (half - life) ⇒ t (half-life) = ln (2) / k
- Since, ln (2) / k is a constant, t (jalf-life) is a constant.
So, the first conclusion is that the first reactions is a first order reaction.
2) Reaction 2.
It is stated that reaction 2 has a half-life that gets longer as the reaction proceeds.
- You can suppose r = k [A]ⁿ, where n = 2 (second order reaction)
- When you solve of t (half-life) you get: t (half-life) = = 1 / ( k [Ao] )
- This shows that for second order reactions, as the reaction proceeds ([Ao] decreases) the half-life increases.
When you do the same analysis for n > 2 (third or higher order reaction), you get the initial concenration raised to a power greater than two in the denominator, driving to the same conclusion, that as the reaction proceeds the half-life gets longer.
So, your second conclusion is that the seond reaction has an order greater than first.
Summarizing the two general conclusions:
- the first reactions is a first order reaction.
- the second one should have an order greater than first.
That is the choice d. The first reaction is a first order reaction, the second one should have an order greater than first.