Question

I’m stuck can some one help me

Answer 1

3) Midpoint is (-4,0.5)

Option A is correct.

4) Midpoint is (2.5,0)

Option B is correct.

5) The factors are (x+4)(x-7)

Option C is correct.

6) The factors are (x+4)(x+2)

Option A is correct.

Explanation:

Question 3

Find midpoint of the following:

(2,-7), (-10,8)

The formula used to find midpoint is:
`Midpoint=((x_1+x_2)/(2),(y_1+y_2)/(2) )`

We have
`x_1=2, y_1=-7, x_2=-10,y_2=8`

Putting values and finding midpoint

`Midpoint=((x_1+x_2)/(2),(y_1+y_2)/(2) )\\Midpoint=((2-10)/(2),(-7+8)/(2) )\\Midpoint=((-8)/(2),(1)/(2) )\\Midpoint=(-4,0.5 )`

So, Midpoint is (-4,0.5)

Option A is correct.

Question 4

Find midpoint of the following:

(2,-10), (3,10)

The formula used to find midpoint is:
`Midpoint=((x_1+x_2)/(2),(y_1+y_2)/(2) )`

We have
`x_1=2, y_1=-10, x_2=3,y_2=10`

Putting values and finding midpoint

`Midpoint=((x_1+x_2)/(2),(y_1+y_2)/(2) )\\Midpoint=((2+3)/(2),(-10+10)/(2) )\\Midpoint=((5)/(2),(0)/(2) )\\Midpoint=(2.5,0 )`

So, Midpoint is (2.5,0)

Option B is correct.

Question 5

Factor each completely

`x^2-3x-28`

We will break the middle term and find factors

`x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)`

So, the factors are (x+4)(x-7)

Option C is correct.

Question 6

Factor each completely

`x^2+6x+8`

We will break the middle term and find factors

`x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)`

So, the factors are (x+4)(x+2)

Option A is correct.