Answer:
= 11.8 Ω
Step-by-step explanation:
Using the equation;
RT = Rr [1 + α (T -Tr)
Where;
RT = Resistance of conductor at temperature T
Rr = Resistance of conductor at reference temperature Tr
α = Temperature coefficient of resistance at reference temperature Tr
Therefore;
RT = 10 Ω [ 1 + 0.004( 65-20)]
= 10 ( 1 + 0.004(45))
= 11.8 Ω