1 Answer

BSG · Answer 1 · 2020-12-10T15:39:08+0000

Answer:

$\large\boxed{C.\ (25+25\sqrt3)\ in^2}$

Explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

A_S=a^2

a - length of side

The formula of an area of an equilateral triangle:

$A_T=(a^2\sqrt3)/(4)$

a - length of side

Clculate the areas:

SQURE:

$A_S=x^2\ in^2$

TRIANGLE:

$A_T=(x^2\sqrt3)/(4)\ in^2$

The SURFACE AREA of a square pyramid:

$S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot(x^2\sqrt3)/(4)=x^2+x^2\sqrt3$

Put x = 5:

$S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2$

Please log in or register to add a comment.