Question

A charge of 4.5x10^-5 C is placed in an electric field with a strength of 2.0x10^4 N/C. What is the electric force acting on the charge?

Answer 1

Answer:0.9 N is correct:)))

Step-by-step explanation:

Answer 2

0.9 N

Step-by-step explanation:

The electric force acting on a charge is given by:

`F=qE`

where

q is the magnitude of the charge

E is the strength of the electric field

In this problem, we have

`q=4.5\cdot 10^(-5)C` is the charge

`E=2.0\cdot 10^4 N/C` is the strength of the electric field

Substituting into the equation, we find

`F=(4.5\cdot 10^(-5)C)(2.0\cdot 10^4 N/C)=0.9 N`