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Which statement about y = x2 − x3 is true?

a.It is not a function.

b.It is an even function.

c.It is neither an odd nor an even function.

d.It is an odd function.

2 Answers

1 vote

Answer:

Option c. It is neither an odd nor an even function.

Explanation:

The equation
y = x^2 - x^3 is a function, because there is a single value of y for each value of the domain x.

To test if it is an even function we must do
y = f(-x). If
f(-x) = f(x) then it is an even function.

If
f(-x) = -f(x) then it is an odd function


y = f(-x) = (-x) ^ 2 - (- x) ^ 3

Simplifying we have:


y = x ^ 2 + x ^ 3

f(-x) is not equal to f(x) so the function is not even.

f(-x) is not equal to -f(x) so the function is not odd.

THE correct answer is the option c

User Andrew Ferrier
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ANSWER

c.It is neither an odd nor an even function.

EXPLANATION

The given function is


y = f(x) = {x}^(2) - {x}^(3)

If this function is odd, then f(-a)=-f(a).


f( - a) = {( - a)}^(2) - {( - a)}^(3)


f( - a) = {( a)}^(2) + {( a)}^(3)

Now ,


f( a) = {( a)}^(2) - {( a)}^(3)


- f( a) = - {( a)}^(2) + {( a)}^(3)

Since


f( - a) \\e - f(a)

The function is not odd.

Also if the function is even, then


f( a) = f( - a)

Since


f( a) \\e f( - a)

the function is not even.

Hence the function is neither even nor odd.

User Vss
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