Answer:
The triangle does not exist because sin(A)/a can not be equal to sin(B)/b
Explanation:
we know that
step 1
Find the measure of angle B
Applying the law of sines
![(sin(A))/(a)=(sin(B))/(b)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lby95pzvkovprr4zmyzfzbg2sapud41k7d.png)
we have
![A=30\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3gjxkan83nbl09w767qbyuuwi3mo0d4f65.png)
![sin(30\°)=1/2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/egpya9lzag79yjttilyfgfgfdrm9o8f645.png)
![a=6\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sv2g0pewgf7rdr5btytn2ecddpl26d43hj.png)
![b=18\ units](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ffszd52o0s9pk4hrl7lvldf1ki1jl5fa7h.png)
substitute
![((1/2))/(6)=(sin(B))/(18)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uafd25clftrohlb51rpuju683citq5yw10.png)
![(1)/(12)=(sin(B))/(18)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rlvdvexgu9wdzcyclrzky2uggdz9htrtxj.png)
![sin(B)=(18)/(12)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bfmnhy29yfudw4l8rl1hsfabe21nzkj16n.png)
![sin(B)=(3)/(2)=1.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dfro0ncvlyl6861qau73glsw71toir0utn.png)
Remember that the value of sine can not be greater than 1
therefore
The triangle does not exist because sin(A)/a can not be equal to sin(B)/b