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How many ways can 15 people be chosen from a group of 22

User MartinWebb
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1 Answer

4 votes

Answer:


170544\text{ ways}

Explanation:

If we don't care about the order (like if we pick Bob then Joe vs Joe then Bob), then a formula is
\frac{n!}k!{(n-k)!} where we are picking k items from a list of n items

In our case, n=22 and k=15

Therefore, there are
(22!)/(15!(22-15)!)=


(22*21*20*19*18*17*16)/((7)!)=


(22*21*20*19*18*17*16)/(7*6*5*4*3*2*1)=


(2*11*7*3*5*4*19*6*3*17*16)/(7*6*5*4*3*2*1)=


11*19*3*17*16=


170544\text{ ways}

User Dwineman
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